Let's Go Fly A Kite - The Solutions
March 24, 2008 When we graph the lines we see that one diagonal runs from (0, 30) to (30, 30), for a length of 30 units, and the other diagonal runs from (15, 0) to (15, 40) for a length of 40 units. To find the area of the kite we’ll use the formula A=(1/2)d1d2 A = (1/2)(30)(40) A = 600 sq units.
To solve this one we’ll use the Pythagorean Theorem (the distance formula can also be used). For the shorter sides: 152 + 102 = c2 225 + 100 = 325 c = 5√13 For the longer sides: 152 + 302 = c2 225 + 900 = 1125 c = 15√5 Since there are two long sides and two short sides we know the perimeter is: 10√13 + 30√5 units
In the first problem we determined that the diagonals were 30 units and 40 units so the average of the two diagonals is (30 + 40)/2 = 35 units. So we know that the tail Jordana made was (1.5)(35) = 52.5 units, to the nearest tenth.
To solve this one we will use the Pythagorean Theorem (with the string being the hypotenuse). 602 + x2 = 1002 3600 + x2 = 10,000 x2 = 6400 x = 80 yards
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