The Ever-Changing Olympics - The Solutions
August 11, 2008
10,625 – 241 = 10,384 (10,384/241)(100) = 4309%
First, let’s figure out the sum of their weights using the average equation (sum/number of items = average)
(a + b + c + d + e + f + g + h)/8 = 250.5 a + b + c + d + e + f + g + h = 2004
Thus if the heaviest guy weighed 264, we can substitute that in for one of the variables and solve for the sum of the remaining unknown guys. a + b + c + d + e + f + g + 264 = 2004 a + b + c + d + e + f + g = 1740 Thus the average weight of the remaining guys is 1740/7 = 248.6 pounds, to the nearest tenth.
1.65 meters (3.281 feet/1 meter) = 5.41 feet, to the nearest hundredth.
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